Author Topic: Repeating numbers  (Read 5730 times)

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Paul

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Repeating numbers
« on: November 07, 2015, 10:46:04 PM »
Hi, Can anyone tell me what the chances of one of the last four numbers repeating is?

Dane

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Re: Repeating numbers
« Reply #1 on: November 08, 2015, 09:14:42 AM »
Hi, Can anyone tell me what the chances of one of the last four numbers repeating is?

Sure! If four different numbers out of 37 have come ,
the answer is 4/37.

scepticus

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Re: Repeating numbers
« Reply #2 on: November 08, 2015, 10:55:34 PM »
Hi, Can anyone tell me what the chances of one of the last four numbers repeating is?

For a 50% chance I think the answer is  2.4
and for a 95% chance I think  the answer is 3.2 Paul

« Last Edit: November 08, 2015, 11:01:35 PM by scepticus »

Mike

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Re: Repeating numbers
« Reply #3 on: November 09, 2015, 08:25:55 AM »
scepticus,

What on earth are you talking about? what does 2.4 and 3.2 refer to?

@ Paul,

Dane's answer is correct.
« Last Edit: November 09, 2015, 01:55:53 PM by Mike »

scepticus

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Re: Repeating numbers
« Reply #4 on: November 09, 2015, 02:26:40 PM »
scepticus,

What on earth are you talking about? what does 2.4 and 3.2 refer to?

@ Paul,

Dane's answer is correct.
The question referred to "one of the four"repeating.
There   are four numbers so to get the probability that one will match we take the square root of 4 and multiply by
a) 1.2 for a 50% chance and
b) by 1.6 for a 95% chance
or have I misunderstood the question?

Real

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Re: Repeating numbers
« Reply #5 on: November 09, 2015, 05:23:47 PM »
Well we can solve this problem using Scep's  nine block..

X 1 2 3 4
1 x 2 3 4
1 2 x 3 4
1 x 2 3 4

Thus the answer is....108

Mike

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Re: Repeating numbers
« Reply #6 on: November 09, 2015, 05:40:05 PM »
There   are four numbers so to get the probability that one will match we take the square root of 4 and multiply by
a) 1.2 for a 50% chance and
b) by 1.6 for a 95% chance

Dog

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Re: Repeating numbers
« Reply #7 on: November 09, 2015, 05:44:33 PM »
So do you  accept that to get any 3 from 4 we simply multiply by 4  -  in the form of
111x
11x1
1x11
x111  ?

Lol !!!

Ruff Ruff?

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Re: Repeating numbers
« Reply #8 on: November 09, 2015, 09:25:44 PM »
Wait a minute what's going in in here?

sqzbox

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Re: Repeating numbers
« Reply #9 on: November 10, 2015, 03:20:33 AM »
My submission would be 42.

But Paul, really, your question implies a misunderstanding of probability. The correct answer is, indeed, 4/37 as has been stated already. But what I would surmise from your question is that you think that by choosing a predetermined 4 numbers, in this case the last 4, that this will somehow be different to simply choosing ANY 4 numbers.  It is not. Choose your numbers any way you like, the probability of one of those coming up on the next spin will always be 4/37.

scepticus

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Re: Repeating numbers
« Reply #10 on: November 10, 2015, 05:07:49 AM »
My submission would be 42.

But Paul, really, your question implies a misunderstanding of probability. The correct answer is, indeed, 4/37 as has been stated already. But what I would surmise from your question is that you think that by choosing a predetermined 4 numbers, in this case the last 4, that this will somehow be different to simply choosing ANY 4 numbers.  It is not. Choose your numbers any way you like, the probability of one of those coming up on the next spin will always be 4/37.
Yes. I misunderstood the question .
I think, though , that what he wants to know is how many spins he needs to bet before one of his numbers hits.

Paul

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Re: Repeating numbers
« Reply #11 on: November 10, 2015, 06:15:45 AM »
Thank you all for your help regarding one of the last four numbers repeating at single zero roulette.
I agree that the answer is 4/37.
At one standard deviation over 111 spins I calculate that one of the last 4 numbers would repeat between 15.25 and 8.73 times and at 3 SD over 111 spins I calculate it to be between 21.81 and 8,73 times. The cruncher is 4 SD giving a result over 111 spins of between 25.08 and 0.hits
Are my calculations correct?

Reyth

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Re: Repeating numbers
« Reply #12 on: November 10, 2015, 12:57:48 PM »
Is what you typed correct that 4 SD also has 0 hits?

scepticus

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Re: Repeating numbers
« Reply #13 on: November 11, 2015, 12:48:34 AM »
Well we can solve this problem using Scep's  nine block..

X 1 2 3 4
1 x 2 3 4
1 2 x 3 4
1 x 2 3 4

Thus the answer is....108
I thought you would offer Paul your super - duper LAST FIVE NUMBERS system. LOL
and even your chart has a duplicate !
« Last Edit: November 11, 2015, 12:50:17 AM by scepticus »

Paul

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Re: Repeating numbers
« Reply #14 on: November 11, 2015, 06:28:38 PM »
There was an error in the 3SD . It should have been 21.81 and 2.19.
For the benefit of those who seem to be having trouble understanding my original question, I was asking what the chances are  of one of the last 4 numbers repeating in single 0 roulette. I agree that the simple answer is 4/37 but is there more to it?