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Author Topic: Scep' s roulette strategies .  (Read 102830 times)

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scepticus

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Re: Scep' s roulette strategies .
« Reply #435 on: January 30, 2018, 08:13:41 PM »
To understand 3 from 4 .
Hold up your hand
Bend forward  the finger nearest your thumb-
Counting from your small finger you now have
1-2-3-bend-
Now straighten your finger  and bend the one next to that .
Now you have 1-2- bend 4.
Now straighten your finger and bend the one next to your little finger .
Now you have 1 bend 2-3-4
Now straighten your finger and bend your little finger .
Now you have- bend 2-3-4.
Now apply all those 4 different Trebles to each of the 9 lines of ANY block and start the calculations to give all the remaining  Trebles / Sets of three.
When I showed this the first time I used X instead of bend but what is the difference ?
 

scepticus

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Re: Scep' s roulette strategies .
« Reply #436 on: January 30, 2018, 08:19:52 PM »
Real
It is not that you are slow learners - just that you are not interested. You guys don't believe me no matter what I say so the best thing to do is to Do It Yourself. If you cannot understand how to calculate it  ask an - er- mathematician. You might believe him or her .
BTW
You haven't proved there are not a guaranteed 3 wins in 4 .  Why not if you think it is rubbish ?
 
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scepticus

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Re: Scep' s roulette strategies .
« Reply #437 on: February 02, 2018, 04:17:32 PM »
What you have  to understand , mike ( and A.N. Other ) is that the 9 block has no relation to roulette . I am only using it for roulette. It really is only maths . It guarantees that within any 4 spins of the wheel there will be one line with at least 3 wins in that   no matter the results - the “effects “ of your “ Cause”.
Take your 74 number scenario.
Dozens 1-2-1-3
The first 2 numbers are in first  , the 1st Dozen and the second in the 2nd Dozen.
111222333
123123123
123231312
231123 312
As you can see from your chosen Block 3 , after two  spins ALL but 2 of the lines containing their First as 2 and 3 have been eliminated as they now contain,at most , 2 numbers . As a treble contains 3 numbers these cannot be the sought guaranteed treble .(Which does not mean that their 2 numbers cannot win but they cannot be the sought treble.)

Which lines now are the most likely to contain the sought treble using Probability Theory ? The lines with 2 numbers correct- the lines with one correct -or   the lines with none correct in the first two spins? Haven’t some possibilities been eliminated ? And therefore the remaining ones now have a better chance than we first did this exercise ?

 
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scepticus

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Re: Scep' s roulette strategies .
« Reply #438 on: February 07, 2018, 05:17:23 PM »
If we are betting on the dozens and list all possible results over 2 spins we get the following .
1-1-1-2-2-2-3-3-3
1-2-3-1-2-3-1-2-3
No matter which downward line you choose the chance that one of the two will win is 5/4 in our favour .   Zero excepted , of course,but it has only a 1 in 37 chance 
Question . Can we make use of this knowledge ?
The same applies to columns  but dozens can  be cheaper to bet .
« Last Edit: February 07, 2018, 05:19:18 PM by scepticus »
 
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scepticus

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Re: Scep' s roulette strategies .
« Reply #439 on: February 11, 2018, 06:18:53 PM »
Oops !
I have to start from scratch. O.K. here goes.
Each of the 9 lines needs four bets . These are to cover each of the 4 Sets of Three
1-2-3-x
1-2-x-4
1-x-3-4
x-2-3-4
So we are using a 36 chip bank.
So first we bet the 1-1-1-2-2-2-3-3-3- each with 3 chips covering the 3 bets 1-2-3-/1-2-4/ and 1-3-4
27  chips bet.
Your turn now Mike  with your first number and chosen block.
 

scepticus

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Re: Scep' s roulette strategies .
« Reply #440 on: February 13, 2018, 05:53:14 PM »
 No response yet . I wonder if the AP now see that using Virtual Bets  is sometimes necessary ?
 

Jesper

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Re: Scep' s roulette strategies .
« Reply #441 on: February 13, 2018, 06:06:05 PM »
They think AHH JUST ONCE AGAIN. They know from many posts in many fora, that's is junk or you do not despite 100 of times not success to tell how it works. The majority can not be accused to be stupid, it is up to you to make it understandable or confess it is junk
 

scepticus

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Re: Scep' s roulette strategies .
« Reply #442 on: February 13, 2018, 06:37:38 PM »
YOU have to prove it is junk . When did I say that  those  who did not understand it were stupid ?
I challenge you to get a mathematician to prove that it is junk . They will never agree  that it will be profitable " In the Long Run" - but junk ? I think not.
 l have been willing to show it  on a Real Table  , AP were not . Why not ? Because there method of AP is Junk !
Plenty  of talk -but  No,Action ! LOL !
 

Jesper

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Re: Scep' s roulette strategies .
« Reply #443 on: February 13, 2018, 07:05:32 PM »
The burden to deliver proof it not the rest of the civilised world population, that belongs to you. A myriad of posts which not show any which the rest of us including  experts in math and games.  It is still junk until you proof it at a standard an educated professor or an other expert can agree, you have up to now just failed. Since years!!

That's is the pure fact.  Write it down in a way it is free from nonsense.
 

scepticus

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Re: Scep' s roulette strategies .
« Reply #444 on: February 13, 2018, 07:49:26 PM »
Do I really need to draw pictures ?
Each line needs to be taken as the four possible variations of 3 from 4 .
This gives you 9x4 "lines of 3  which  means 36 bets. Strangely, no one has pointed out the obvious . That betting 36
chips to win 27 is not to be recommended . So , to profit, we must  eliminate some of the possibles.
There is a guarantee that at least one of these 36 lines will be All- Correct- barring a zero which is Expected to win
once in an average 37 spins.
If there is a guarantee of one correct line does this not suggest that there  will be some that  MUST be wrong? And , if this is so, eliminating these may give us an Edge ?   
 

Mike

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Re: Scep' s roulette strategies .
« Reply #445 on: February 14, 2018, 02:21:52 PM »
Although I don't understand exactly how you're playing the system, from what you've said about "elimination" I'm guessing the logic goes something like this (I'm using the even chances to keep it simple, but the principle is the same for any bet):

For two red/black outcomes, the only possible alternatives are

RR
RB
BR
BB

You arrive at the table and see the last number is 16. This immediately allows you eliminate half of the possibilities, so you are left with BR or BB. But this elimination doesn't give you any advantage, because the next outcome is still just as likely to be R as B. And similarly if you're playing dozens. Eliminating lines from the block will always leave some in which the next bet is equally likely to be a low, middle or high dozen, so it's just as much of guess as if you hadn't eliminated any lines in the first place. This must always be so, because outcomes are independent.

 

Jesper

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Re: Scep' s roulette strategies .
« Reply #446 on: February 14, 2018, 03:42:48 PM »
Yes it is true there is a certain combinations, and on EC:s we eliminate half every time a spin happen (on NOZ)
until we are done.  But how will it help us betting better than chance? The result will be by chance.  I can spend a lot of effort telling how I prepare for the game, everthing can be true, but has nothing to do really with the game. Such I  have brown shoes, true but of no use for the play..
 

scepticus

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Re: Scep' s roulette strategies .
« Reply #447 on: February 14, 2018, 05:46:22 PM »
Mike
You still haven’t grasped the idea of 3 from 4 . Nor do you accept that I MUST use the first two spins as Virtual Bets. And you AP keep saying that Virtual Bets are “useless “ !

If you do get round to eliminating the possibles you will find that the remainders  fall into one of the 4 possibilities of 3 from 4.

After the first 2 Virtual spins you will be left with 2 possibilities with only 1 bet left and 2 with 2 bets left. 
These correspond to 1-2-3 /1-2-4 /1-3-4- / and 2-3-4.

 If “anything can win “ the last two spins then it is obvious that we should choose  the one which can be bet as a double. We find that , to do this, we need to make two bets with odds of 8/1 for each which means odds on the two of  7/2.As some of the possible have been eliminated then there are NOT   9 possibles left . Which means that the odds are in our favour.
Do the elimination process to “ get the idea “ .

Even if you still think this does not make sense then you must , at least , accept  that my 2 from 9 gives correct odds but will lose to the zero - 2 units in every average 37 spins.
BUT - the casino is as much at risk of Random as the Bettor.

 

scepticus

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Re: Scep' s roulette strategies .
« Reply #448 on: February 14, 2018, 05:49:30 PM »
Mike
You are good at criticising Systems .
Why not post your AP and give us a chance to criticise your form of AP ?
 

MickyP

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Re: Scep' s roulette strategies .
« Reply #449 on: February 14, 2018, 06:58:21 PM »
I'd like to give Mike the benefit of the doubt. I'm sure he is a man of his word and I look forward to reading his posts going forward. Having said this, I would like to see Mike open meaningful discussions on AP methods as well; not to criticise him but rather to learn from him.