### Author Topic: EC  (Read 2786 times)

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#### Sputnik

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##### EC
« on: April 30, 2016, 06:03:18 PM »
You know dozen, where two dozen can hit for 10 15 20 25 30 times in a row.
Now you can get the same random distribution with EC with same probability or odds 1 in 3.

Singles is dozen 1
Series of two is dozen 2
Series of Three or higher is dozen 3

Now when you compare dozen random flow with EC random flow you get the same results in the short term. Some clever member might argue that you get 1000 singles and 500 series of two and 250 series of Three, but with random fluctaion and variance that is not the case in short term, but would apply if you make larger statistical sample.

I can play any existing dozen system or method and apply same for EC.
This works flat betting and with smooth progression.

EC distribution with dozen odds:

1
1
1 dozen 3
2
1 dozen 1
2 dozen 1
1 dozen 1
2 dozen 1 - strike 5 times
2 dozen 2
1
1 dozen 2
2
1 dozen 1 - strike 7 times
1
1 dozen 3
2
1 dozen 1
1
1 dozen 3
2
1 dozen 1
1
1 dozen 3
1
1
1
2
1 dozen 1
2 dozen 1 - strike 8 times
2 dozen 2
1
1 dozen 2 - strike 4 times
2
2
2 dozen 3
2
2
2
1
1 dozen 2
2
2 dozen 2
1
1 dozen 2
2
2 dozen 2
1
1
1 dozen 3 - strike 8 times
1
2
1 dozen 1
1 dozen 2
2
1 dozen 1 - strike 3 times
1
1 dozen 3
1
2
1 dozen 1
2 dozen 1 - strike 4 times
2 dozen 2
1
1 dozen 2
2
1 dozen 1
2 dozen 1
1 dozen 1
2
2 dozen 2
1
2 dozen 1
1 dozen 1
1 dozen 2
2
1 dozen 1
2 dozen 1 - strike 13 times
2
2 dozen 3
1
1
1 dozen 3
2
2
2 dozen 3
1
2 dozen 1 - strike 6 times
2 dozen 2
1
2 dozen 1
1 dozen 1
1 dozen 2
2
2 dozen 2 - strike 6 times
1
1
1 dozen 3
1
2
2 dozen 3
2
2
1
1 dozen 2
2
2 dozen 2
1
1 dozen 2
2
2
2 dozen 3
1
1 dozen 2 - strike 9 times
2
1 dozen 1 - strike 2 times
1
1 dozen 3
2
2
2 dozen 3
2
1
2 dozen 1
1 dozen 1
2 dozen 1 - strike 6 times
2

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#### Reyth

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##### Re: EC
« Reply #1 on: April 30, 2016, 06:26:13 PM »
Generally an EC will only miss around 25+ times consecutively; I have never heard of 30 BUT a dozen will miss consecutively around 41+ times, so how do we reconcile this?

#### Sputnik

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##### Re: EC
« Reply #2 on: October 29, 2016, 09:08:16 AM »
Ok i search for this topic and will continue...PART 1 DOZEN AS EC BET

Resume:
1 in 2 with 1 in 3 odds

Dozen 1 = Single
Dozen 2 = Series of two
Dozen 3 = Series of Three and higher

You can backtrack the random bits and you will see that the EC produce the same distribution using this methodology as the dozen does...
I will now just compare dozen methods that can be played in the same way using the EC

How to play one Dozen or one Column

You track the dozen or column for 6 spins and write them down so you get a line.

1
3
2
2
3
1

Now you can start to play and you will follow that line for 6 times and bet that the same will occur, 2 in a row.

12
32
21
22 win 2 of the same.
3
1

Now you have to complete the group of 18 outcomes so you continue to write down the  numbers in the same order as before

121
321
211
221
31
11

Keep doing that until you have a complete group of 18 outcomes whit the principal of 1/3 - like this:

121
321
211
221
313
113

Now you can start over again and track the first 6 outcomes and list them like this:

1
1
3
3
2
3

When you have six you start to play after that line.
Now the first bet is 1 the second is 1 and the third is 3 and you hope to get 2 of the same.

Lets say you didn't get 2 of the same and the line look like this:

12
12
21
32
23
12

Now the bet selection change.
Now you want to get 3 different results.
That they alternate like 231 or 312.

So lets take a look at the line again and if we have
12 then we will bet 3 or if we got 31 we would bet 2.

122
122
211
321 win its alternate.
23
12

So there is 2 different ways you will try to gain a profit.
After we have the first line of 6 outcomes then we will try to get 2 of the same whit the second line for 6 attempts.
If the second line loses then we will try to get a alternate whit the third line, like 123 213 312 for 6 times.

Here you have a grahp Spilbank Hamburg 2005 01 01 Tabel 1

This is how it looks when you tracking the groups whit the principal of 1/3 whit 18 outcomes.

SPIELBANK HAMBURG 2005 01 01 TABEL 1

231
113
213
221
323
213

How to play one Dozen or one Column.

You track the dozen or column for 6 spins and write them down so you get a line.

1
3
2
2
3
1

Now you can start to play and you will follow that line for 6 times and bet that the same will occur, 2 in a row.

12
32
21
22 win 2 of the same.
3
1

Now you have to complete the group of 18 outcomes so you continue to write down the  numbers in the same order as before

121
321
211
221
31
11

Keep doing that until you have a complete group of 18 outcomes whit the principal of 1/3 - like this:

121
321
211
221
313
113

Now you can start over again and track the first 6 outcomes and list them like this:

1
1
3
3
2
3

When you have six you start to play after that line.
Now the first bet is 1 the second is 1 and the third is 3 and you hope to get 2 of the same.

Lets say you didn't get 2 of the same and the line look like this:

12
12
21
32
23
12

Now the bet selection change.
Now you want to get 3 different results.
That they alternate like 231 or 312.

So lets take a look at the line again and if we have
12 then we will bet 3 or if we got 31 we would bet 2.

122
122
211
321 win its alternate.
23
12

So there is 2 different ways you will try to gain a profit.
After we have the first line of 6 outcomes then we will try to get 2 of the same whit the second line for 6 attempts.
If the second line loses then we will try to get a alternate whit the third line, like 123 213 312 for 6 times.
One other option or alternative is to aim for 121 212 or 323 insted of 123 and so on ...

Here you have a grahp Spilbank Hamburg 2005 01 01 Tabel 1

This is how it looks when you tracking the groups whit the principal of 1/3 whit 18 outcomes.

231
113
213
221
323
213

How to play the EC method using the dozen method above

Here we can make the samepel smaller with variant 1 ...

331 W
221 W
331 W
112 W

This is how the random bits look like for the clustering sequense above.
Code: [Select]
`1112211121111221111212122`Variant two is to only play after one single or one serie of two or one serie of Three - then you will have the odds 1 in 9 ...
For example serie of Three.

Then the losing combination look like this

RRR B RR or BBB R BB

So if you see a serie of Three you aim for a repeat of a serie
If you lose you get a single and bet for a repeat of a single
If you lose then you bet that the last serie will be Three in a row as the first one

The winning sequense look like this

333 W
332 W
331 W
322 W
321 W
311 LW
313 LLW
323 LLW
312 LLL

Cheers

« Last Edit: October 29, 2016, 09:10:08 AM by Sputnik »

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#### Reyth

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##### Re: EC
« Reply #3 on: October 29, 2016, 09:27:11 AM »
Wow nice matrix systems!

Fascinating!  The accuracy is amazing!!

Let's talk about bankroll for the dozen system:

1 1 2 3 4 6 = 17
2 2 4 6 8 12 = 34

for a total loss of 51 units.

So far I have come nowehere close to even losing on the first (2nd) column!

I wonder how many times in a row you can lose both columns...  Made 30 units in like 5 mins.
« Last Edit: October 29, 2016, 09:51:48 AM by Reyth »

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#### Sputnik

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##### Re: EC
« Reply #4 on: October 29, 2016, 09:34:54 AM »
Here is one example using RNG clustering into Three column or 2 x 3 bets or 6 attempts.
As you can see the random bits has to get chaotic if you are going to lose.

For example

123
213
321

Assume you get following sequense and lose your first Three bets and get into recovery mode.

123
21
32

Now you would aim for 212 and 323 and if your first formation was 121 you would aim for 213 and  321 but this is just one assumption.
Some one would argue there will be at least one repeat among 9 trails and first aim for one repeat and then after that once more aim for one repeat.
Based upon the idea above would be a total of five attempts.

111 W
111
213

133 L
222 W
113

131 L
311 L
333 W

111 W
111
321

211 L
131 L
111 W

112 W
131
113

111 W
313
221

321 W
223
321

131 L
113 W
312
« Last Edit: October 29, 2016, 12:31:04 PM by Sputnik »

#### Reyth

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##### Re: EC
« Reply #5 on: October 29, 2016, 10:00:42 AM »
So on the EC method the idea would be to track all 3 EC's and bet 3 columns at a time...

I don't know if I am clear but I think it that you bet groupings of streaks/chop.  So on the dozens you want 6 previous results but on the EC's you only want 3?

So it would go like:

RBRRB

Which would be:

1
1
2

So on the first result if we are betting SAME then we want a RED to confirm our result of 1 and thus we would bet RED?

B

12(loss)
1
2

How would we keep betting here and what would be the results if the sequence continued BRBRBBR?

I just don't get when and what we bet on the EC's...

The EC's are good because you can track 3 at a time but on dozens you can only track one set of 3.
« Last Edit: October 29, 2016, 10:04:27 AM by Reyth »

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#### Sputnik

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##### Re: EC
« Reply #6 on: October 29, 2016, 10:20:17 AM »

Your first example is correct and i will make a step by step explination.
Just want to mention that you can clustering the random bits with any amount of attempts.

First event is a serie of Three which means we have dozen Three BBB
That would become the number 3

3

The secound event is a serie of two and are dozen two RR

3
2

The third event is a serie of Three and are dozen 3 BBB

3
2
3

Now you wait for the next colour to show RED and then bet it will become a serie.
There is a loop hole as it does not matter if there is a serie of Three or two you win in any case.
But the intention is to aim for a repeat of a serie of Three.
Forget about it and recoginice it now.

The fourth event is a single and we lose our first bet.

31
2
3

Our fifth bet is on a serie of two to follow by a serie of two and we got a serie of Three and win.

31
23
3

So if there is more of singles then series of two and Three and higher but both serie formation win you are equal.
And there is as many series as there is singles.

Cheers

#### Reyth

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##### Re: EC
« Reply #7 on: October 29, 2016, 10:41:57 AM »
Hmmm.  So why not just do EC's as singles like:

RBRRBBRRBRBBRRBRBBBB which would be:

RBB WL
BRR WL
RBR WW
RBB WL
BRB WW
BRB WW
RBB WW

Winning 11 units in 14 spins.
« Last Edit: October 29, 2016, 11:16:54 AM by Reyth »

#### Bayes

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##### Re: EC
« Reply #8 on: October 29, 2016, 10:49:59 AM »
I don't want to derail this thread but here's another way you can get EC's from Dozens. It's based on the fact that the probability of any given dozen hitting at least twice in 5 spins is 0.5 (actually, the exact probability is 52.1%):

So we will have 3 EC's; one for each dozen. Set out the outcomes 5 at a time in matrix format (H = high, M = middle, L = low dozens):

H       M       L
----------------------------------------
H H H L M           W         L        L
M L H H M           W      W          L
M M L M H              L    W          L
H H M L H           W          L       L
H M L H M           W      W          L

So each of the columns H,M,L represent 'true' even chances because the probability of a W/L is approx. 0.5. Suppose you think that in the next row the losing streak for the low dozen will come to an end. You could then bet that there will be at least 2 low dozens in the next 5 outcomes.
« Last Edit: October 31, 2016, 05:18:52 PM by Bayes »

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#### Sputnik

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##### Re: EC
« Reply #9 on: October 29, 2016, 11:13:22 AM »
Hmmm.  So why not just do EC's as singles like:

RBRRBBRRBRBBRRB[/size]BRRBBBB which would be:

RBB WL
BRR WL
RBR WW
RBB WL
BRB WW
BRB WW
RBB WW

Winning 11 units in 14 spins.
Write from mobile phone... you dont get The same odds and strike ratio
« Last Edit: October 29, 2016, 12:30:19 PM by Sputnik »

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#### Sputnik

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##### Re: EC
« Reply #10 on: October 29, 2016, 01:05:43 PM »
Wow nice matrix systems!

Fascinating!  The accuracy is amazing!!

Let's talk about bankroll for the dozen system:

1 1 2 3 4 6 = 17
2 2 4 6 8 12 = 34

for a total loss of 51 units.

So far I have come nowehere close to even losing on the first (2nd) column!

I wonder how many times in a row you can lose both columns...  Made 30 units in like 5 mins.

I test real casino spins and the hit ratio is very good and effective.
Got to the 2nd level once during 350 trails.
All won.

Code: [Select]
`113 W131231132 L233 W211211 L321 W322113 W111232332 W113113111 W232221313 L313 L113 W333 W333213212 L311 L332 W112 W233122111 W223111331 W133331313 L W132 L 313 L113 W232311331 W111122113 W311212131 L111 W232`

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#### Sputnik

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##### Re: EC
« Reply #11 on: October 29, 2016, 02:15:53 PM »
I don't want to derail this thread but here's another way you can get EC's from Dozens. It's based on the fact that the probability of any given dozen hitting 2 or 3 times in 5 spins is 0.5 (actually, the exact probability is 0.494 to 3 d.p.):

So we will have 3 EC's; one for each dozen. Set out the outcomes 5 at a time in matrix format (H = high, M = middle, L = low dozens):

H       M       L
----------------------------------------
H H H L M           W         L        L
M L H H M           W      W          L
M M L M H              L    W          L
H H M L H           W          L       L
H M L H M           W      W          L

So each of the columns H,M,L represent 'true' even chances because the probability of a W/L is approx. 0.5. Suppose you think that in the next row the losing streak for the low dozen will come to an end. You could then bet that there will be at least 2 low dozens in the next 5 outcomes.

Here is Another way using dozen method with Bayes or my way.
You see two hitting dozen, then bet the third one as it should show within 5 events.
Using the EC position ...

My way with random bits:

Code: [Select]
`1112211 L121 W111221 W11121 W2122111 W1112112 W112 L21 L2111 W12221222 L111 L1111111212112 W112 L21 L222 W1222 L111 L1111212111 L`
Bayes way:
Code: [Select]
`H H H L M WON           ML H WON H M M M L M  LOSSH  WON            H H M L  WONH           H M L  WONH M  `

« Last Edit: October 29, 2016, 02:22:35 PM by Sputnik »

#### Sputnik

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##### Re: EC
« Reply #12 on: October 29, 2016, 02:28:56 PM »

Another variant assymetric random bits.
You see once dozen and bet the other two to get singles - so you bet against repeats.

All existing dozen methods can be played with EC play ...
Dozen play and EC play.

Dozen:

Code: [Select]
`12 W3 W1 W3 W1 W2 W3 W1 W2 W2 L231 W1 L21 W3 W2 W3 W3 L12 W2 L11 L111`
EC PLAY

Code: [Select]
`11122 L1 W1 L1 W21 W1 W1122 L1 W1 L1 W121 W2 L1 L2211 L1 W11121 W1 W21 W1 W22 L1 L2 W1 L1 W11`

#### Reyth

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##### Re: EC
« Reply #13 on: October 29, 2016, 08:43:03 PM »
I don't understand how the EC streaks translate to a "dozen position" and we must only look at groupings of 3 EC spins?  So BBBBBBRRR translates to 3 3 3?

#### Sputnik

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##### Re: EC
« Reply #14 on: October 30, 2016, 09:50:08 AM »
I don't understand how the EC streaks translate to a "dozen position" and we must only look at groupings of 3 EC spins?  So BBBBBBRRR translates to 3 3 3?

R

B

Here above i have one single and do not know anything about the furthere.
One single is dozen one and i now want to play that there will be at least two dozen one in a row.

R

B
B L

I lose and did not get two singles in a row, only one, that means dozen one only hit once.
Next i don't know if it will become a serie of two ( dozen two ) or if it will become a serie of Three or higher ( dozen Three ) so i wait and observe.

R

B
B
B
B

I got four black in a row and have a serie of Three or higher, that means dozen Three.
Next when when reds come i will bet that once of this two dozen will repeat once as we many times see two dozen hit several times in a row.

R

B
B
B
B

R

Now i will play that there will be a single (dozen one).

R

B
B L
B
B

R
R L

I lose and will now play that i get a serie of Three or higher.
If i lose all Three bets then i have dozen 123 alternating and have a show each with no repeat present.
That means one single and one serie of Three and one serie of two.
They can come in any combinations as Three uniq ones.

R

B
B L
B
B

R
R L
L
B

If you would see dozen Three - Three times in a row - then that would be Three series of Three or higher in a row after each other - for example RRR BBBBB RRRR