Compute the loss of a true sample of 37 spins and make your conclussion.

See also "whois the smartest player", the one who plays 1 unit on a dozen or the one who plays one unit on the other 2 dozens

The answer is not so simple...

If the odds for a

**specific** number to come at least once within 37 spins is 1/37 or 2.7%, then for

**any** number to appear at least once within 37 spins is 64.86 % (on average).

The possibility for a

** specific** number to come two times in a row is (1 in 37*37) = once every 1369 results, but for

**any** number is (1 in 1369 / 37) = once every 37 results or 2.7% (on average).

So theoretically it's equally possible but I've never seen the same number twice in a row to be absent for such long as a single number can be absent (600+ spins)

If you doubt about it, you might want to check your records and/or run simulations.

If you agree with me, then we conclude that this is the best option for selecting a single number.