A strong system based on the American wheel can be applied by betting:
40 $ on 1st column
40 $ on 3rd column
40 $ on 3rd dozen
60 $ on low
6 $ on each: 0,00,20,23
There are 4 chances to win (6 x 36) 216 - 204 = +12
There are 20 possibilities to win (2 x 60 + 3 x 40 OR 3 x 40 + 3 x 40) 240 - 204 = +36
There are 14 possibilities to lose (2 x 60 OR 3 x 40) 120 - 204 = -84
Since the total number of winning opportunities are almost double than the losing ones, we could use this proportion in our favor.
After a losing result increase proportionally all the bets with each and every successive spin till you recover and be on the positive again.
Let me show you an example;
Say you lost 84 bucks regardless of which number, you increase the columns and dozen by 40 bucks each, increase the low by 60 bucks, increase 0,00,20,23 by 6 each.
80 $ on 1st column
80 $ on 3rd column
80 $ on 3rd dozen
120 $ on low
12 $ on each: 0,00,20,23
If you lose again before you fully recover, raise bets like this:
120 $ on 1st column
120 $ on 3rd column
120 $ on 3rd dozen
180 $ on low
18 $ on each: 0,00,20,23
By keeping the proportionally betting schedule even the worst variance could not last for long because you are covering large continuous sectors of the wheel.
The 1st + 3rd columns are covering 11 continuous numbers from 1 side and 8 continuous numbers from the other side of the wheel.
While the combination of Low and 3rd dozen starts when the columns stop for 9 continuous around 0 and another 9 continuous around the 00.
Therefore the losses will be here and there, rare and far from each other.
I believe by covering so many numbers the variance could be reduced effectively in combination with a short progression.
Yes, winning could become a formality but this could result in no excitment after plenty of winning sessions.
I guess that this is preferable than losing sessions.