A strong system based on the American wheel can be applied by betting:

40 $ on 1st column

40 $ on 3rd column

40 $ on 3rd dozen

60 $ on low

6 $ on each: 0,00,20,23

There are 4 chances to win (6 x 36) 216 - 204 = +12

There are 20 possibilities to win (2 x 60 + 3 x 40 **OR** 3 x 40 + 3 x 40) 240 - 204 = +36

There are 14 possibilities to lose (2 x 60 OR 3 x 40) 120 - 204 = -84

Since the total number of winning opportunities are almost double than the losing ones, we could use this proportion in our favor.

After a losing result increase proportionally all the bets with each and every successive spin till you recover and be on the positive again.

Let me show you an example;

Say you lost 84 bucks regardless of which number, you increase the columns and dozen by 40 bucks each, increase the low by 60 bucks, increase 0,00,20,23 by 6 each.

80 $ on 1st column

80 $ on 3rd column

80 $ on 3rd dozen

120 $ on low

12 $ on each: 0,00,20,23

If you lose again before you fully recover, raise bets like this:

120 $ on 1st column

120 $ on 3rd column

120 $ on 3rd dozen

180 $ on low

18 $ on each: 0,00,20,23

By keeping the proportionally betting schedule even the worst variance could not last for long because you are covering large continuous sectors of the wheel.

The 1st + 3rd columns are covering 11 continuous numbers from 1 side and 8 continuous numbers from the other side of the wheel.

While the combination of Low and 3rd dozen starts when the columns stop for 9 continuous around 0 and another 9 continuous around the 00.

Therefore the losses will be here and there, rare and far from each other.

I believe by covering so many numbers the variance could be reduced effectively in combination with a short progression.

Yes, winning could become a formality but this could result in no excitment after plenty of winning sessions.

I guess that this is preferable than losing sessions.