Gentlemen,

After reading the Gut articles by the respected and learned members, in forums, I admit I cant understand the techniques.

Nevertheless,

Let me have a few words, what I think, of some simple ideas to bet a different kind of GUT.

Say,

1]law of third, 24numbers hit in 37spins.

2]ONLY 17numbers to, ONLY 31,32,33,34,35,36 numbers hit in 37SPINS, possible, but highly unlikely.

The method:

in 37spin.

1st spin= hit=1 , unhit=0

Wait till=hit=20, unhit=17.

then bet the unhit 17numbers.

This simply mean we hope for 24hit, to materialized in the remaining spins, FLATBET.

17numbers bet=17chip,

1st attempt,lose=17u,total=-17. win=+19

2nd attempt,lose=17u, total=-34u. Win=+19=+2nett.

3rd attempt,lose=17u,total=-51. win=+19=-15net.

so on.

Thus from the,

hit=20numbers to the 24 intended hit=

24-20=4more hit.

17numbers bet=win=+19.

16numbers bet=win=+20.

15numbers bet=win=+21.

14numbers bet=win=+22..total=+82

Debacle=

approximately...

first loss=-17units.=-17

2nd loss=-17units.=-34

3rd loss=-17units.=-51

4th loss=-17units.=-68

5th loss=-17units=-85

offset by,

aproximately winning=

17numbers bet=win=+19.

16numbers bet=win=+20.

15numbers bet=win=+21.

14numbers bet=win=+22..total=+82

Total spins=9spins.

thus 37spins-9spins=28th spin

This mean, in my shallow opinion.

BEST attempt to bet,

hoping for 24 HITs, in 37 spins=

17 unhit numbers, at the 28th spins.

In simple explaination,

U wait for 17unhit, that happen in the 28th spins,

[or more, say 29th, 30th, so on...]

Then u bet the remaining unhit, in the next 9spins.

The worst losses=

none hit in the next 9spins!

=-17x9=-153unit losses, in none hit, in remaining 9spins!

----------------

only ONE hit,hit in the next 9spins!

approximately..

win=+19,

losses=-16x8=-128u=-109.

--------------------

only 2hit in the next 9spins!

1st win=+19,

2nd win=+20=+39

next straight losses=-15x7=105=-66

-----------------------------

only 3hit in the next 9spins!

1st win=+19,

2nd win=+20=+39

3rd win=+21=+60

next straight losses,-14x6=-84=-24u

------------------

only 4hit in the next 9spins!

1st win=+19,

2nd win=+20=+39

3rd win=+21=+60

4th win=+22=+82

next straight losses,-13x5=-65=+17

and so on.

above just an example of how the risk u face.

OF COURSE , u stop at first win!

Summmary.

Wait for 17unhit to happen at ,

at least at the 28th spin.

ie.

eg.

at 28th spin,

hit=20, unhit=-17.

so for law of third,

24number hit in 37 spins,

there MAY be, 4 hit in next 9spins.

So u take the risk that the

remaining 4hit will happen,

in the next 9spins...to 24numbers hit in 37spins.

1st spin=lose.=-17,total=-17

2nd=lose.=-17,total=-17

3rd=lose.=-17,total=-34

4th=lose.=-17,total=-51

5th=lose.=-17,total=-68

6th=hit=bet17u=+19,=-49

7th=hit=bet16u=+20,=-29

8th=hit=bet15u=+21,=-8

9th=hit=bet14u=+22,=+14

===============

So u take the risk that if 20numbers hit,

the remaining 4hit will happen,

in the next 9spins...to 24numbers hit in 37spins

or in other way, if there is less than 20 hit in 28th spins, then the opportunity better.

---------------

IF,

at the 28th spin,

there 20hit, thus risk 4 in remaining 9spins.

there 19 hit, thus risk 5 in remaining 9spins.

there 18 hit, thus risk 6 in remaining 9spins.

there 17 hit, thus risk 7 in remaining 9spins.

there 16 hit, thus risk 8 in remaining 9spins.

there 15 hit, thus risk 9 in remaining 9spins.

===============================

or U may reduce the parameter...

===========================

say,

at the 20th spin.

there ....

.

there 7hit, thus risk=17in remaining 17spins.

there 8hit, thus risk=16in remaining 17spins.

there9 hit, thus risk=15in remaining 17spins.

there10 hit, thus risk=14in remaining 17spins.

there11 hit, thus risk=13in remaining 17spins.

there 12 hit, thus risk=12 in remaining 17spins.

there 13hit, thus risk=11 in remaining 17spins.

there 14 hit, thus risk=10 in remaining 17spins.

there 15hit, thus risk=9in remaining 17spins.

there 16 hit, thus risk=8in remaining 17spins.

there 17 hit, thus risk=7 in remaining 17spins.

there 18 hit, thus risk=6in remaining 17spins.

there 19 hit, thus risk=5in remaining 17spins.

there 20 hit, thus risk=4 in remaining 17spins.

there 21 hit, thus risk=3in remaining 17spins.

there 22 hit, thus risk=2in remaining 17spins.

there 23 hit, thus risk=1in remaining 17spins.

there 24 hit, thus risk=0in remaining 17spins.

What u think?