I found this post because I have noticed a new phenomenon associated with equal distribution that I am calling, "Distribution Disparity". This is where a selected set of numbers have not spun for a disproportionately larger time period which indicates that the Law of the Third has caught those numbers.
The indicator for this theoretically would be the number that has not spun the longest when compared to the number that has spun most recently within the set.
My theory is that if this gap grows too large, you are looking at a "compromised" set of numbers that is made up of mosty sleepers.
I'm not a statistician nor a mathematician but I just know there is a formula that I can use to determine this...
My thoughts were to try and determine average variance for the Law of the Third and use that to compare with the set of numbers. Maybe its that simple?
I mean, I dunno maybe its just the larger number vs. the average of the set...
Ok, the set of numbers that I am interested in has 10 elements; Number of trials needed to get 10 different numbers is 11.00...
This is simply not helpful in itself.
Ok, I guess it will simply be:
The average time since all numbers have spun vs. the number with the lowest time in the set.
Pretty sure this will work as a disparity indicator.
Ok, no. Averages muddle the picture.
Starting to work with the lowest number in the set (which represents the state of the board) & adding 74 to that number (they are splits).
Here's what I have:
184 <=== clogged flow
104 <=== within average flow parameters
229 <=== clogged flow
163 <=== clogged flow (clogs at 169)
95 <=== average state of the board, normal distribution flow
Each of the clogged values are greater than 73 above the average distribution flow of the board. The idea is to identify this when it happens and end the session because when the Law of the Third captures this set, there will be prolonged miss streaks on these numbers.
Maybe I should work with the total average of all the numbers vs. my selected set...
Ya I think typing this out has helped me alot. The key is comparing all the numbers on the board, this is where the answer lies!