What are the odds that a dozen to occur to times?
Mathematical the odd is almost 1/(3^2) , 1 in 9 tries .
This in procentual is 11,11% .
Pretty high I say.
"couple" consist in a progression like this :
(1,3) , (1,3) ,(1,3) ,(1,3) , (1,3), (1,3), (1,3)
this 7 couples
we will bet like this :
1.Pick a random(or how you like) dozen/etc.
a. If we lose go to the next couple (1,3)
b. If we win put 3 unit on the same dozen/etc.
If we lose this 7 couples , we have the next couples :
(2,1) , (3,1) , (3,2) , (4,2) ,( 4,3 ) ,(5,4)....( how much you bankroll can support, i will explain in the comment if you dont understand how I make this couples)
Steps for this :
1.Pick a random dozen.
2.Put 2 units ( the first number) if we lose go to the next couple
3.If we win
- bet on the same dozen with the second number as units
Now if we win the second bet we have like (0,1,2) units profit .
if we lose we have like 1 unit profit , and we stay a the same couple
The sesion is over when you win both the bets.Example
for the second phase :
Let's say we bet on the first dozen (1-12) and we are at the the couple (4,3) .
We lost 19 units .
If the first bet wins , we have 4*3=12 unit
If the second bet lose , we have 12-4 - 3 = 5 units .
Now we pick another dozen , and repet the couple (4,3) .
This is "couple" , by Maes. Sorry for the bad English
EDIT 1 : Because of my math
second couples are :
(3,1) , (3,2) ,(4,3),(5,4) , (7,5),(9,5) ...