What are the odds that a dozen to occur to times?

Mathematical the odd is almost 1/(3^2) , 1 in 9 tries .

This in procentual is 11,11% .

Pretty high I say.

"couple" consist in a progression like this :

(1,3) , (1,3) ,(1,3) ,(1,3) , (1,3), (1,3), (1,3)

this

**7 couples** we will bet like this :

1.Pick a random(or how you like) dozen/etc.

2.Put

**1** unit .

a. If we lose go to the next couple (1,3)

b. If we win put 3 unit on the same dozen/etc.

3.Repet

** 7 **times

If we lose this 7 couples , we have the next couples :

(2,1) , (3,1) , (3,2) , (4,2) ,( 4,3 ) ,(5,4)....( how much you bankroll can support, i will explain in the comment if you dont understand how I make this couples)

Steps for this :

1.Pick a random dozen.

2.Put 2 units ( the first number) if we lose go to the next couple

3.If we win

- bet on the same dozen with the second number as units

Now if we win the second bet we have like (0,1,2) units profit .

if we lose we have like 1 unit profit , and

we stay a the same couple .

The sesion is over when you win both the bets.

**Example** for the second phase :

Let's say we bet on the first dozen (1-12) and we are at the the couple (4,3) .

We lost 19 units .

If the first bet wins , we have 4*3=12 unit

If the second bet lose , we have 12-4 - 3 = 5 units .

Now we pick another dozen , and repet the couple (4,3) .

This is "couple" , by Maes. Sorry for the bad English

(.

EDIT 1 : Because of my math

second couples are :

(3,1) , (3,2) ,(4,3),(5,4) , (7,5),(9,5) ...