Stand by the table and look at the matrix,what do you see?

If for example you see as the last spun number the 7,then bet the 7,its 4 neighbours from the left and its 4 neighbours from the right for a total of 9 numbers with 1 unit each.

If this bet wins,repeat the process by adjusting the center of the bet to the new number.

If the bet lost,bet again the same 9 numbers but this time include the new number with its 4 neighbours from the left and right side for a total of 18 numbers.

If you win,return to the 9 numbers betting with the latest spun number.

If you lose twice in a row,there are 2 options,first is to stop and wait for a virtual win,in other words a bet which would have won if you had bet it.

The second option is to bet the previous 18 numbers plus 9 more from the latest number but this time with 4 units on every number (27x4=108)

What I'm doing is to use the second option till I lost it,but on the mean time I'm winning much more bets than the eventual -108 units.

If you win on the first bet (9 numbers) you win 27 units,if you win on the second bet,you would gain 9 units,if you win on the third bet,you would net 9 units.

Alternative option is to stop the session on a net gain of 108 units,thus before losing 3 times in a row.

Whatever way you play it,if you find yourself winning or losing 108 units,you should stop immediately.

A final note,there are cases which the ball lands just 1 or 2 pockets from our betting selection,in other words the 9 pockets segment conflicts with another,on such cases you should extend the range of the central number (last spun number) in order to bet the same amount of numbers but without any gaps and without placing 2 chips on any number.

I've tried with good to very good results,there would be situations which you will lose 3 times in a row,but those will be overwhelmed by the majority of positive ones.