Author Topic: Can someone send me the average?  (Read 691 times)

edgefounder

  • New
  • **
  • Posts: 13
  • Thanked: 9 times
Can someone send me the average?
« on: February 03, 2017, 06:57:01 PM »
Hi,

I'm new to this forum but I like what I see! Quality!

I have a interesting question. Can someone run something on a large scale and
let me know what happens?

I would like to know if you have 20 uniques (17 sleepers) in last 37 spins and you play those 17 numbers and you play for 9 spins you would on average have 6.5 wins on 9 spins since on 46 spins you have on average 26.5 uniques and so you'll be hitting 6.5 of the next 9 spins.

Edge?

Who could run this on a large scale and let me know the results?
« Last Edit: February 03, 2017, 07:01:34 PM by edgefounder »


 
The following users thanked this post: Reyth

Reyth

  • Global Moderator
  • Hero Member
  • *****
  • Posts: 3010
  • Thanked: 795 times
Re: Can someone send me the average?
« Reply #1 on: February 03, 2017, 07:19:02 PM »
Attempting to tackle this.

working...

First draft completed.

debugging...

Not able to pull up a single instance of 20 uniques...

Verifying code accuracy...
« Last Edit: February 03, 2017, 07:50:45 PM by Reyth »
 
The following users thanked this post: edgefounder

edgefounder

  • New
  • **
  • Posts: 13
  • Thanked: 9 times
Re: Can someone send me the average?
« Reply #2 on: February 03, 2017, 07:32:32 PM »
I seriously think that there would be an edge since I ran both simulation on 37 and 46 spins sequence
and on 46 spins you have 26.5 uniques on average.

Are you using roulette Xtreme or something?
« Last Edit: February 03, 2017, 07:54:43 PM by edgefounder »
 

Jesper

  • Hero Member
  • ******
  • Posts: 1138
  • Thanked: 535 times
  • Gender: Male
Re: Can someone send me the average?
« Reply #3 on: February 03, 2017, 08:07:06 PM »
Average never gives an edge!
 

edgefounder

  • New
  • **
  • Posts: 13
  • Thanked: 9 times
Re: Can someone send me the average?
« Reply #4 on: February 03, 2017, 08:15:55 PM »
True, but mathematics gives me the highest feeling of comfort in the game.
 

Reyth

  • Global Moderator
  • Hero Member
  • *****
  • Posts: 3010
  • Thanked: 795 times
Re: Can someone send me the average?
« Reply #5 on: February 03, 2017, 08:28:51 PM »
The software is not bringing up a single instance of 17 sleepers, after 37 spins.

Like I indicated, I need to check the programming to make sure it is accurate...

EDIT: Ya obviously the code is flawed.  I will fix it.
« Last Edit: February 03, 2017, 09:09:35 PM by Reyth »
 

scepticus

  • Hero Member
  • ******
  • Posts: 1666
  • Thanked: 307 times
Re: Can someone send me the average?
« Reply #6 on: February 04, 2017, 03:27:44 AM »
The software is not bringing up a single instance of 17 sleepers, after 37 spins.

Like I indicated, I need to check the programming to make sure it is accurate...

EDIT: Ya obviously the code is flawed.  I will fix it.

Reyth
Isn't 12 sleepers  in 37 spins nearer the mark ? The Law of the Third ?
 

Reyth

  • Global Moderator
  • Hero Member
  • *****
  • Posts: 3010
  • Thanked: 795 times
Re: Can someone send me the average?
« Reply #7 on: February 04, 2017, 04:38:35 AM »
Exactly.  I was in the little roulette player's room and I realized how the software must be flawed. :D
 

Trilobite

  • Mature Member
  • ***
  • Posts: 298
  • Thanked: 97 times
Re: Can someone send me the average?
« Reply #8 on: February 04, 2017, 06:23:19 AM »
Your software might be flawed, but you still won't see a lot of "20 uniques/17 sleepers" in 37 spins.

It does happen, but not often so you would need a huge spin sample to test this for an edge.

If there was an edge, which, even without testing I can guarantee there isn't, then you would need to have an awful lot of time on your hands to play it.

You could make a bot, but there would at times be vast gaps between betting opportunities.
 

Trilobite

  • Mature Member
  • ***
  • Posts: 298
  • Thanked: 97 times
Re: Can someone send me the average?
« Reply #9 on: February 04, 2017, 06:25:42 AM »
you play those 17 numbers and you play for 9 spins you would on average have 6.5 wins on 9 spins...

Why?

The average would be closer to 4 wins on 9 spins I would think.
« Last Edit: February 04, 2017, 06:32:49 AM by Trilobite »
 

Trilobite

  • Mature Member
  • ***
  • Posts: 298
  • Thanked: 97 times
Re: Can someone send me the average?
« Reply #10 on: February 04, 2017, 06:31:53 AM »
...if you have 20 uniques (17 sleepers) in last 37 spins...

If I ever noticed this happening I would rather play the 20 uniques for a max of 2 spins with a 1.2. progression as a spot play and be done with it.

It's a lot of numbers to get chipped up on though.
« Last Edit: February 04, 2017, 06:34:25 AM by Trilobite »
 

Trilobite

  • Mature Member
  • ***
  • Posts: 298
  • Thanked: 97 times
Re: Can someone send me the average?
« Reply #11 on: February 04, 2017, 07:09:57 AM »
Hey, sorry my bad.

Just ignore what I've posted. I misunderstood your question.  :-[

..too tired to be posting on forums, need to sleep.
 

edgefounder

  • New
  • **
  • Posts: 13
  • Thanked: 9 times
Re: Can someone send me the average?
« Reply #12 on: February 04, 2017, 08:30:27 AM »
Hi,

17 sleepers in 37 spins happens in about 3.43% of the times which makes it playable. One out of 30 runs.

Hope this helps.

Edgefounder
 
The following users thanked this post: Reyth

Reyth

  • Global Moderator
  • Hero Member
  • *****
  • Posts: 3010
  • Thanked: 795 times
Re: Can someone send me the average?
« Reply #13 on: February 04, 2017, 09:17:46 AM »
I have to sleep too.  Maybe I will fix this tomorrow.
 

Bayes

  • Veteran Member
  • ****
  • Posts: 576
  • Thanked: 430 times
  • roulettician.com
Re: Can someone send me the average?
« Reply #14 on: February 04, 2017, 10:20:53 AM »
I would like to know if you have 20 uniques (17 sleepers) in last 37 spins and you play those 17 numbers and you play for 9 spins you would on average have 6.5 wins on 9 spins since on 46 spins you have on average 26.5 uniques and so you'll be hitting 6.5 of the next 9 spins.

This can't be right because if you think about it, you're betting less than half the numbers so the number of wins should be less than half the number of spins (i.e. less than half of 9). The formula is very simple: multiply the probability of a win by the number of spins to get the average number of wins. So in this case you would win 17/37 x 9 = 4.135 on average or 4 to the nearest whole number.
 
The following users thanked this post: edgefounder