### Author Topic: Force the losing end come to you or allow the losing end unfold by it self  (Read 1297 times)

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#### Sputnik

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##### Force the losing end come to you or allow the losing end unfold by it self
« on: July 31, 2016, 09:51:13 AM »
Force the losing end come to you or allow the losing end unfold by it self

Hypotes

You have eight patterns into groups of three.
The aim is to Catch at least one repeat among does eight patterns.
You have above 99% probability that you will at least have one repeat which means that at least one pattern will fall into sleep and not show.
In reality you get at least 1 to 16 repeats and above for each complete cycle.

Code: [Select]
`111121112122222212221211`
Question

1) If you betting nonstop on a rolling basis you force to find the end with eigth alternating patterns to show with no repeat and you lose.

2) You pinpoint out one repeat within a cycle and then wait for the cycle to become complete where all eight patterns has a show before you start a new cycle and pinpoint out one repeat, so each cycle has to become complete with all eight patterns to show and unfold naturally, before you start a new attack.
This way you need to hit one cycle window among other cycle window where there is no imbalance.

Is there a difference?

Cheers
« Last Edit: July 31, 2016, 09:54:25 AM by Sputnik »

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#### Reyth

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##### Re: Force the losing end come to you or allow the losing end unfold by it self
« Reply #1 on: July 31, 2016, 11:12:36 AM »
Hmmm, this seems like the "resetting the seed" question that I always seem to think of when it comes to wanting to "clear the decks" and "get a fresh start".

I guess if we wait for balance to show that's about the best we can do right?  At least we tried...

#### Sputnik

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##### Re: Force the losing end come to you or allow the losing end unfold by it self
« Reply #2 on: July 31, 2016, 12:28:57 PM »
30 repeats
Code: [Select]
`1 2 2 122 <2 1 2 212 <1 1 2 112 <2 1 1 211 <1 2 1 121 <1 2 2 1222 1 2 2122 2 2 222 <2 1 1 2112 1 2 2121 2 2 1222 2 2 2221 2 1 1212 2 2 2221 1 1 111 <1 2 2 1221 2 2 1222 2 2 2222 2 2 2222 1 2 2121 2 1 1211 2 2 1222 1 2 2121 2 1 1211 2 2 1221 1 2 1121 2 2 1221 1 1 1112 1 2 2122 1 2 2121 2 1 1212 2 2 2221 1 1 1111 2 1 1211 1 2 1122 1 1 2112 2 2 2222 2 1 221 <`
8 repeats
Code: [Select]
`1 2 1 121 <2 1 2 212 <1 1 2 112 <2 1 2 2121 1 1 111 <2 1 1 211 <1 2 2 122 <1 1 1 111 1 1 2 112 1 1 2 112 2 2 2 222 <1 1 2 1121 2 2 1221 2 2 1222 2 2 2222 2 1 221 <`
7 repeats
Code: [Select]
`2 1 2 212 <1 2 2 122 <1 1 1 111 <2 2 1 221 <1 1 1 1111 1 1 1112 2 1 2212 1 1 211 <2 1 1 211 2 1 2 2121 2 2 1222 2 2 222 <2 1 1 2111 2 1 121 <1 1 2 112 <`
8 repeats
Code: [Select]
`2 2 2 222 <1 2 2 122 <1 1 2 112 <1 2 1 121 <1 1 1 111 <1 2 1 121 2 2 1 221 <2 1 2 212 <2 1 2 2121 1 2 1121 1 2 1121 2 1 1212 1 2 2121 1 2 1122 2 1 2212 1 1 211 <`

#### MrBac

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##### Re: Force the losing end come to you or allow the losing end unfold by it self
« Reply #3 on: July 31, 2016, 12:41:10 PM »
I would have thought that by playing non-stop you would be subjected to more variance, while sacrificing possible wins.

If the pattern you are betting is 222, and the next group is 112, is that considered a win on the third bet, then restart with a new pattern, or do you keeping betting 222?

What are the maths to back up this stated 99% probability?

#### Sputnik

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##### Re: Force the losing end come to you or allow the losing end unfold by it self
« Reply #4 on: July 31, 2016, 01:05:38 PM »
This is furhter development - see attach files ...
A Dice with six sides has 98.5% alternating with no repeat or 1.5% and we talk about 8 side.

The difference is that i have the solution for the loop hole they describe.
I know how to cover no bet into one bet cover RBB RBR situation and cover both options with one single bet. Which not can be done if you read what the Birthday Paradox autor say at Espirit.
I have two solution where you can cover all posibilitys even if you get a tie situation.
« Last Edit: July 31, 2016, 01:29:13 PM by Sputnik »

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#### Sputnik

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##### Re: Force the losing end come to you or allow the losing end unfold by it self
« Reply #5 on: August 02, 2016, 04:26:53 AM »
One thing that strike me is to use a static template to match or not match.
So you use a line Before any outcome show and match and not match and change the probability or narrow down the amount of possibilitys to give you a losing sequense as you limit the equlibirium.

If you don't understand this i just can say that i reduce 12 attempts to cover all posibilitys into 9 attempts, how does that make you feel?

It would look like this:

1. R
2. B
3. R
4. B
5. R
6. B
7. R
8. B

1. RBR
2. BRR
3. RBR W
4. B
5. R
6. B
7. R
8. B

1. RRR
2. BBR
3. RRR W
4. B
5. R
6. B
7. R
8. B

1. RBB
2. BRR
3. RRB
4. BRR W
5. R
6. B
7. R
8. B

1. RRB
2. BBR
3. RRB W
4. B
5. R
6. B
7. R
8. B

1. RRB
2. BRR
3. RRB W
4. B
5. R
6. B
7. R
8. B

1. RBR
2. BBB
3. RBB L
4. BBR L
5. RRB L
6. BBR W
7. R
8. B

1. RBB
2. BBR
3. RRR
4. BBR W
5. R
6. B
7. R
8. B

1. RRR
2. BRR
3. RBR
4. BBB
5. RBR W
6. B
7. R
8. B

1. RRB
2. BBR
3. RRB W
4. B
5. R
6. B
7. R
8. B

1. R
2. B
3. R
4. B
5. R
6. B
7. R
8. B
« Last Edit: August 02, 2016, 04:52:05 AM by Sputnik »

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