Hi new to the website.

Testing a system with live autowheel data. I have 20,000 spins recorded by myself to test a system which soo far has not lost in 20,000 spins and made a profit of about £4,000 using a bank of £1,700.

Would I would be greatly know the below...

I have worked out the odds of 12 numbers not showing in 10 consecutive spins is

25/37^10 = 0.0198 (approx 50/1)

The odds of this happening twice in a row is

0.0198 X 0.0198 = 0.000392 (approx 2500/1)

But from my data of 20,000 spins it shows on average that 12 numbers not coming out in 10 spins is actually 1/200 and not 1/50!

Would this be because I'm using the same 12 numbers each time...and then waiting for one of my 12 numbers to land before I start betting...instead of playing any of the 37 number of the table!??

Also say for example my special 12 numbers are

1,2,3,4,5,6,7,8,9,10,11,12

If number 7 lands for example, I place my bets on the above 12 numbers and play them over 10 spins and hope one lands so I wins and then start the process again.

Say if number 7 landed and I placed my bets on my 12 number over 10 spins and none won.

Then the next time 7 comes out it "should" win within 10 spins.

The odds says 1/2500 chance of this not happening but again I have played over 20,000 spins and it hasn't happened once.

Based on the above example would the Maths reflect correctly what I am trying to work out in terms of probability!? As doesn't seem right.

Any help would be great...have asked a few mathes forum online but not everyone understands roulette and system.

Thanks