I guess each + represent a sequence where the hit appeared after the 6th spin, right?
The big question is what do we do after the 6th spin? Do we keep betting? Or we only bet the first 6 spins after a hit?
If we keep betting after the 6th spin then the actual length of a + sequence if of great importance.
The probabilistic problem that makes the puzzle hard to solve is that after the 6th spin, can theoretically begin a new cycle, so betting after the 6th spin can be considered a new sequence and equal to betting in the first 6 spins. (theoretically there is no difference since roulette has no memory)
Yes + sign pass and minus sign hit.
Now you talking about the real thing and i will give example.
1) Bayes says that one hit or several hits within a cycle count as one.
This means that you can track the random bits in cycles of six with no hit or hit within does cycles.
If you chart and tracking them as Yes and No you will get the same distribution as Red and Black.
2) Assume you follow one color only, then color you follow has to hit before you can attack, so if you would bet against six singles to catch at least a serie of two, then it would be the same using the following approch with quads. You see one quad hit then you bet for six attempts (one cycle) no hit and you get a Black and if you win you get a serie of Red.
NOTE this is based upon my understanding.
I know GF - but i put my money on does event that has a hit to hit more, then following a slepping path that might never end (stop sleeping).
Feel free to make your own conclusion - i assume you get more results of the random bits with option one (not meaning more action or attacks) just the charting and tracking results, then option two.